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Capacitors in Series Calculator

Find equivalent capacitance (1/Ceq = 1/C1 + 1/C2 + …), voltage distribution, total charge Q, and stored energy for up to 6 series capacitors. Includes the product-over-sum shortcut, a live circuit diagram, and a full series vs parallel comparison.

⚡ Voltage (V)

🔧 Capacitor Values

📐 Circuit Diagram

⚙️ Formula

1/Ceq = 1/C1 + 1/C2 + ...
Key Principle: In series circuits, the charge Q is the same on all capacitors. The total voltage divides across them inversely proportional to capacitance. Equivalent capacitance is always less than the smallest capacitor.

📋 Voltage Distribution

CapacitorCapacitanceVoltage Drop

📊 Results

Voltage (V)

12V

Equivalent C

50.00µF

Total Charge

0.60mC

Equivalent Capacitance

50.00 µF

Total Charge (Q = Ceq × V)

0.60 mC

Stored Energy (E = ½CV²)

3.60 mJ
💡 Remember: Capacitors in series behave like resistors in parallel — use the same reciprocal formula. For exactly two capacitors: Ceq = (C₁ × C₂) / (C₁ + C₂).

Capacitors in Series Calculator — Complete Guide to Series Capacitance

This capacitors in series calculator instantly finds the equivalent capacitance for up to 6 capacitors connected end-to-end in a single current path using the reciprocal formula 1/Ceq = 1/C1 + 1/C2 + … + 1/Cn. It also shows the voltage across each capacitor, the shared charge Q, and the total stored energy — with a live circuit diagram that updates in real time. Use it for capacitor voltage-rating checks, AC coupling design, LC resonator tuning, and any circuit where you need to achieve a lower-than-standard capacitance value.

Quick Reference: Series Capacitor Formulas

QuantityFormulaNotes
Equivalent Capacitance1/Ceq = 1/C1 + 1/C2 + … + 1/CnAlways < smallest C
Two Capacitors (shortcut)Ceq = (C1 × C2) / (C1 + C2)Product over sum
n Equal CapacitorsCeq = C / ne.g., 3× 15µF → 5µF
Charge (same on all)Q = Ceq × VtotalAll caps share same Q
Voltage across CiVi = Q / CiSmaller C → larger V
Stored EnergyE = ½ × Ceq × V²Also Ei = ½ × Q² / Ci

How to Use This Capacitors in Series Calculator

Enter the supply voltage, then set the capacitance value and unit (pF, nF, µF, mF, F) for each capacitor. Click + Add Capacitor to include up to 6 capacitors. The calculator instantly shows Ceq, total charge, stored energy, and the voltage across every individual capacitor — and the live circuit diagram updates automatically.

The Series Capacitor Formula Explained

When capacitors are wired in series, only one current path exists. Charge can only accumulate on the outermost plates — the inner plates must remain neutral because they are electrically isolated. As a result, every capacitor stores exactly the same charge Q regardless of its individual capacitance. Since Q = C × V, a smaller capacitor must have a larger voltage across it to store the same charge. The total "effort" to store charge — the equivalent capacitance — is found by adding the reciprocals:

1/Ceq = 1/C1 + 1/C2 + 1/C3 + … + 1/Cn

The result is always less than the smallest individual capacitor. Adding more capacitors in series always reduces Ceq.

Product-Over-Sum Shortcut (Exactly Two Capacitors)

Ceq = (C1 × C2) / (C1 + C2)

Example: 10 µF and 22 µF → (10 × 22) / (10 + 22) = 220 / 32 = 6.875 µF

Equal-Capacitors Shortcut

Ceq = C / n

Example: Three 15 µF capacitors in series → 15 / 3 = 5 µF

Why Series Capacitance Decreases

Think of a capacitor as two plates separated by a gap. Connecting two capacitors in series is equivalent to placing four plates in a row — the inner two are isolated and don't help store charge, so the effective plate separation doubles while the plate area stays the same. Since C = ε × A / d, doubling d halves C. More capacitors in series means even greater effective separation and even lower capacitance — the exact opposite of series resistors, which simply add up.

Voltage Distribution in Series Capacitors

Because all capacitors share the same charge Q, the voltage across each one is Vi = Q / Ci. Smaller capacitors carry a proportionally higher voltage. This is critical for safety:

Q = Ceq × Vtotal (find the shared charge first)
Then: V1 = Q / C1, V2 = Q / C2, …
Check: V1 + V2 + … = Vtotal

Worked Examples

Example 1: Two Capacitors — Product-Over-Sum

Problem: 10 µF and 22 µF in series across 12 V. Find Ceq, Q, and voltages.

Ceq = (10 × 22) / (10 + 22) = 6.875 µF

Q = 6.875 × 12 = 82.5 µC

V1 = 82.5 / 10 = 8.25 V   V2 = 82.5 / 22 = 3.75 V   ✓ 8.25 + 3.75 = 12 V

Example 2: Three Equal Capacitors

Problem: Three 15 µF capacitors in series across 9 V.

Ceq = 15 / 3 = 5 µF

Q = 5 × 9 = 45 µC   V each = 45 / 15 = 3 V ✓ (3 × 3 = 9 V)

Example 3: Voltage Rating Check

Problem: Two 100 V–rated capacitors — 100 µF and 220 µF — in series across 100 V. Are they safe?

Ceq = (100 × 220) / 320 = 68.75 µF   Q = 68.75 × 100 = 6875 µC

V1 = 6875 / 100 = 68.75 V ✓   V2 = 6875 / 220 = 31.25 V ✓ Both safe.

Series vs Parallel Capacitors — Complete Comparison

Capacitors in SeriesCapacitors in Parallel
Formula1/Ceq = Σ(1/Ci)Ceq = ΣCi
Result vs individual capsAlways < smallest CAlways > largest C
Voltage across each capDivides (inversely with C)Same on all
Charge on each capSame on allDivides (proportional to C)
Analogous to resistorsParallel resistorsSeries resistors
Used forVoltage sharing, LC tuning, AC couplingFiltering, decoupling, energy storage

Capacitance Units Reference

UnitSymbolValue in FaradsTypical Use
FaradF1 FSupercapacitors, energy storage
MillifaradmF10⁻³ FLarge filter/power caps
MicrofaradµF10⁻⁶ FElectrolytic, film caps
NanofaradnF10⁻⁹ FCeramic and film caps
PicofaradpF10⁻¹² FRF, timing, parasitic caps

Practical Applications of Series Capacitors

Common Mistakes to Avoid

Frequently Asked Questions

Why is series capacitance always less than the smallest capacitor?

Adding positive reciprocals always gives a sum whose reciprocal is smaller than any single term. Physically, the weakest (smallest) capacitor limits the total stored charge per volt of the whole chain.

Can I mix different capacitor types in series?

Yes, but exercise caution. Different types have different leakage currents, ESR, and voltage characteristics. Add balancing resistors across electrolytics to equalise DC voltage distribution.

How do I use series capacitors to hit a specific target value?

For two capacitors, rearrange the product-over-sum formula: given Ctarget and C1, find C2 = (Ctarget × C1) / (C1 − Ctarget). Experiment with values using this calculator.

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