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RLC Series Resonance Simulation

Analyze Impedance, Reactance, Phase Angles, and Resonant Peaks

Resistance (R)
Ω
1 Ω500 Ω
Inductance (L)
mH
0.5 mH150 mH
Capacitance (C)
µF
0.1 µF50 µF
Source Voltage (Vrms)
V
1 V120 V
AC Frequency (f)
Hz
10 Hz6 kHz
Reactance Status
Inductive Mode

Current lags Voltage (inductive reactance dominates)

⚙️ Series RLC Schematic & Live Probes
AC SOURCE 12.0 V | 1.0 kHz R 50.0 Ω VR = 11.79V L 10.0 mH XL = 62.8 Ω VL = 14.81V C 2.20 µF XC = 72.3 Ω VC = 17.06V SERIES CURRENT (I) 235.8 mA
📈 Resonance Peak Analysis
Current (mA) vs Frequency Log Scale
Resonant Peak
240.00 mA
Q-Factor
1.34
📐 Phasor Vectors
Reactance Complex Plane (+j)
Phase Angle (θ)
0.0°
IN-PHASE
Total Impedance (Z)
50.00 Ω
Total opposition to current
Resonant Frequency (fr)
1068.72 Hz
Reactance balance point
Net Reactance (X)
0.00 Ω
Inductive/Capacitive load
Active Power (P)
2.88 W
Real energy consumed
1. Reactance & Resonance
XL = 2πfL | XC = 1/(2πfC) | fr = 1/(2π√LC)
2. Impedance
Z = √[R² + (XL − XC)²]
3. Current & Phase
I = V / Z | θ = tan−1((XL − XC)/R)
4. Power & Quality Factor
P = I² R | Q = ωL/R | BW = fr/Q
Step 1: Calculate Reactances
XL = 2π × f × L
XC = 1 / (2π × f × C)
XL = 314.16Ω | XC = 318.31Ω
Step 2: Calculate Impedance
Z = √[R² + (XL − XC)²]
Z = √[100² + (314.16 − 318.31)²] = 100.09Ω
Step 3: Calculate Current
I = V / Z
P = I² × R
I = 12 / 100.09 = 0.1199A | P = 1.438W
Step 4: Calculate Phase Angle
φ = tan−1((XL − XC)/R)
φ = tan−1((−4.15)/100) = −2.38° (Capacitive)
Step 5: Calculate Resonant Frequency
fr = 1 / (2π√(LC))
fr = 1 / (2π√(0.010000 × 0.0000022000)) = 1.07 kHz
Step 6: Calculate Quality Factor
Q = (ωL) / R = fr / BW
Q = 62.83 / 50 = 1.34 | BW = 1068.72 / 1.34 = 797.55 Hz

RLC Series Resonance Calculator — Complete Guide to Series RLC Circuit Analysis

This RLC series resonance calculator analyses a series RLC circuit at any frequency. Enter R, L, C, source voltage V, and frequency f to instantly find the resonant frequency (fr = 1/2π√LC), inductive reactance XL = 2πfL, capacitive reactance XC = 1/(2πfC), total impedance Z = √(R² + (XL−XC)²), circuit current I = V/Z, phase angle φ, quality factor Q = (1/R)√(L/C), and bandwidth BW = fr/Q — with a live circuit diagram, resonance curve, and phasor diagram. Use it for band-pass filter design, LC oscillator analysis, RF tuner modelling, and power factor correction.

Quick Reference: Series RLC Formulas

QuantityFormulaAt Resonance (f = fr)
Resonant Frequencyfr = 1 / (2π√(LC))
Inductive ReactanceXL = 2πfLXL = XC
Capacitive ReactanceXC = 1 / (2πfC)XC = XL
Total ImpedanceZ = √(R² + (XL−XC)²)Z = R (minimum)
Circuit CurrentI = V / ZI = V/R (maximum)
Phase Angleφ = arctan((XL−XC) / R)φ = 0° (unity PF)
Quality FactorQ = (1/R) × √(L/C)
BandwidthBW = fr / Q
Voltage across RVR = I × RVR = V (all voltage)
Voltage across LVL = I × XLVL = Q × V
Voltage across CVC = I × XCVC = Q × V

What Is Series RLC Resonance?

A series RLC circuit places R, L, and C end-to-end in a single loop driven by an AC source. The same current flows through every component. At the resonant frequency, the inductive reactance XL = 2πfrL equals the capacitive reactance XC = 1/(2πfrC), so they cancel exactly. The total impedance drops to its minimum value (= R), the current rises to its maximum (= V/R), and the voltage and current are perfectly in phase (unity power factor).

Resonant Frequency: fr = 1 / (2π × √(L × C))

At resonance: XL = XC,   Z = R,   I = V/R (maximum),   φ = 0°

Reactance, Impedance, and Phase Angle

Away from resonance, one reactance dominates the other:

Below fr: XC > XL → circuit is capacitive → I leads V (negative φ)

Above fr: XL > XC → circuit is inductive → I lags V (positive φ)

Z = √(R² + (XL − XC)²)     φ = arctan((XL − XC) / R)

Voltage Magnification at Resonance

One of the most remarkable features of a series RLC circuit is that the voltages across L and C can both be Q times larger than the source voltage at resonance. This is called voltage magnification or resonance rise:

VL = VC = Q × Vsource   (at resonance)

Example: Q = 20, V = 12 V → VL = VC = 240 V
Always rate L and C for their peak operating voltages!

Q-Factor and Bandwidth

Q = (1/R) × √(L/C)

In a series circuit, smaller R → higher Q → sharper resonance.
This is the opposite of a parallel RLC where larger R → higher Q.

Bandwidth: BW = fr / Q
Half-power (−3 dB) frequencies: f1 = fr − BW/2,   f2 = fr + BW/2
At f1 and f2: Z = R√2,   I = Imax/√2

Worked Examples

📐 Example 1 — Resonant Frequency & Full Analysis at Resonance
GivenR = 50 Ω  |  L = 10 mH  |  C = 2.2 µF  |  V = 10 V  |  f = fr
Step 1fr = 1 / (2π × √(0.01 × 2.2×10⁻⁶)) = 1,073 Hz
Step 2XL = 2π × 1073 × 0.01 = 67.4 Ω  |  XC = 1 / (2π × 1073 × 2.2×10⁻⁶) = 67.4 Ω ✓ (equal at resonance)
Step 3Z = √(50² + (67.4 − 67.4)²) = √(2500 + 0) = 50 Ω   (minimum — equals R)
Step 4I = V / Z = 10 / 50 = 200 mA   (maximum)  |  Phase φ =   (unity power factor)
Resultfr = 1,073 Hz  |  Z = 50 Ω  |  I = 200 mA  |  φ = 0°
🔍 Example 2 — Q-Factor, Bandwidth & Voltage Magnification
GivenR = 10 Ω  |  L = 10 mH  |  C = 2.2 µF  |  V = 10 V  |  fr = 1,073 Hz
Step 1Q = (1/R) × √(L/C) = (1/10) × √(0.01 / 2.2×10⁻⁶) = (1/10) × 67.4 = 6.74
Step 2BW = fr / Q = 1073 / 6.74 = 159 Hz  |  f1 = 994 Hz  |  f2 = 1,153 Hz
Step 3⚠️ VL = VC = Q × V = 6.74 × 10 = 67.4 V   (across each component at resonance!)
ResultQ = 6.74  |  BW = 159 Hz  |  VL = VC = 67.4 V — rate components accordingly
📊 Example 3 — Off-Resonance: Impedance & Phase Angle
GivenR = 50 Ω  |  f > fr  |  XL = 75 Ω  |  XC = 40 Ω  |  V = 10 V
Step 1Net reactance = XL − XC = 75 − 40 = +35 Ω   (positive → inductive, I lags V)
Step 2Z = √(50² + 35²) = √(2500 + 1225) = √3725 = 61.0 Ω
Step 3φ = arctan(35 / 50) = arctan(0.70) = 35.0°   (inductive — current lags voltage)
Step 4I = V / Z = 10 / 61.0 = 163.9 mA   (less than the 200 mA at resonance)
ResultZ = 61.0 Ω  |  φ = +35° (inductive)  |  I = 163.9 mA

Series vs Parallel RLC Resonance — Complete Comparison

Series RLCParallel RLC (Tank)
Impedance at resonanceMinimum (= R)Maximum (= R)
Current at resonanceMaximum (= V/R)Minimum (= V/R)
Q-factor formulaQ = (1/R)√(L/C)   ↓R → ↑QQ = R√(C/L)   ↑R → ↑Q
Resonant frequencyfr = 1/(2π√LC)fr = 1/(2π√LC)
Below resonanceCapacitive (I leads V)Inductive (I lags V)
Above resonanceInductive (I lags V)Capacitive (I leads V)
Voltage magnificationVL = VC = Q × VsItank = Q × Isource
Main useBand-pass filters, tuned amplifiersOscillators, notch filters, tuners

Practical Applications of Series RLC Circuits

Common Mistakes to Avoid

Frequency Response and Reactance Chart

Frequency vs frXL vs XCCircuit TypePhase AngleImpedance Z
f ≪ frXL ≪ XCCapacitiveφ ≈ −90°Very high (≈ XC)
f < frXL < XCCapacitiveφ < 0°> R
f = frXL = XCResistiveφ = 0°Z = R (minimum)
f > frXL > XCInductiveφ > 0°> R
f ≫ frXL ≫ XCInductiveφ ≈ +90°Very high (≈ XL)

Frequently Asked Questions

What is the resonant frequency of an RLC circuit?

fr = 1 / (2π√(LC)). This is the frequency at which XL = XC, impedance is minimum, and current is maximum. It depends only on L and C, not R.

Does the resistor change the resonant frequency?

No. The resonant frequency fr = 1/(2π√LC) is determined entirely by L and C. R affects the Q-factor, bandwidth, and peak current, but not the frequency at which resonance occurs.

Why can the voltage across L and C exceed the source voltage at resonance?

At resonance VL = VC = Q × Vsource. The reactive voltages are equal and opposite, so they cancel in the total phasor, leaving only VR = Vsource. But each individual reactive component sees Q times the source voltage.

What is the difference between XL and XC?

XL = 2πfL increases with frequency. XC = 1/(2πfC) decreases with frequency. At resonance they are equal. The net reactance X = XL − XC determines the circuit's phase and how far it is from resonance.

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