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Inductors in Series Calculator

Find total equivalent inductance (Leq = L1 + L2 + L3 + …), inductive reactance (XL = 2πfL), voltage distribution, and stored energy for up to 6 series inductors. Includes mutual inductance formulas (aiding & opposing), inductor types guide, and a full series vs parallel comparison.

⚡ Frequency (Hz)

🔧 Inductor Values

📐 Circuit Diagram

⚙️ Formula

Leq = L1 + L2 + L3 + ...
Key Principle: Inductors in series simply add up (like resistors in series). The same current flows through all, and voltage divides proportionally to each inductance. Assumes no mutual coupling (M = 0).

📋 Impedance Distribution

InductorInductanceImpedance (XL)

📊 Results

Frequency

1000 Hz

Total Leq

Total XL

Equivalent Inductance

Total Inductive Reactance (XL = 2πfL)

Stored Energy (E = ½LI²) at 1A

💡 Remember: Inductors in series = simple addition (like resistors in series). For mutual coupling: Leq = L₁ + L₂ ± 2M.

Inductors in Series Calculator — Complete Guide to Series Inductance

This inductors in series calculator instantly finds the total equivalent inductance when multiple inductors are wired end-to-end in a single current path using the simple addition formula Leq = L1 + L2 + … + Ln. It also computes the inductive reactance XL = 2πfLeq at any operating frequency, voltage distribution across each inductor, and total stored energy — with a live circuit diagram. Use it for LC filter design, RF matching networks, multi-stage EMI chokes, transformer winding analysis, and any circuit where you need to combine or fine-tune inductance values.

Quick Reference: Series Inductor Formulas

QuantityFormulaNotes
Total InductanceLeq = L1 + L2 + … + LnAlways > largest L (M = 0)
n Equal InductorsLeq = n × Le.g., 3× 10 mH → 30 mH
Inductive ReactanceXL = 2π × f × LeqOhms; rises with frequency
Voltage across LiVi = (Li / Leq) × VtotalProportional to inductance
Stored EnergyE = ½ × Leq × I²Same current through all
Aiding MutualLeq = L1 + L2 + 2MFields in same direction
Opposing MutualLeq = L1 + L2 − 2MFields in opposite direction

The Series Inductor Formula Explained

When inductors are connected in series, the same current flows through every inductor. Each coil opposes changes in that current independently, so their total opposition — their total inductance — simply adds up:

Leq = L1 + L2 + L3 + … + Ln

The result is always greater than the largest individual inductor. This is identical to resistors in series and the opposite of capacitors in series. The formula assumes no mutual coupling between inductors (M = 0) — i.e., they are physically separated or magnetically shielded.

Inductive Reactance (XL)

Unlike a resistor, an inductor's opposition to current depends on frequency. The higher the frequency, the harder the inductor pushes back against current changes:

XL = 2π × f × L   (in ohms, Ω)

For series inductors: XL(total) = 2π × f × Leq

Example: Leq = 32 mH at f = 1 kHz → XL = 2π × 1000 × 0.032 = 201 Ω

Mutual Inductance in Series Circuits

When inductors are physically close, their magnetic fields interact through mutual inductance M. The total series inductance depends on whether the fields aid or oppose each other:

Aiding (fields in same direction):
Leq = L1 + L2 + 2M

Opposing (fields in opposite direction):
Leq = L1 + L2 − 2M

Coupling coefficient: k = M / √(L1 × L2)   (0 = no coupling, 1 = perfect coupling)

This mutual coupling is intentional in transformers and coupled inductors, and unintentional (parasitic) when two chokes are mounted too close together on a PCB.

Voltage Distribution in Series Inductors

Because all series inductors carry the same current I, the voltage across each is proportional to its inductance. Larger inductors receive more of the total voltage:

Vi = (Li / Leq) × Vtotal   (AC voltage divider)

In the time domain: Vi = Li × (dI/dt)

Worked Examples

Example 1: Two Inductors in Series — Reactance

Problem: 10 mH and 22 mH in series at 1 kHz. Find Leq, XL, and voltage split across 12 V.

Leq = 10 + 22 = 32 mH

XL = 2π × 1000 × 0.032 = 201.1 Ω

V1 = (10/32) × 12 = 3.75 V   V2 = (22/32) × 12 = 8.25 V   ✓ 3.75 + 8.25 = 12 V

Example 2: Three Inductors for Filter Design

Problem: 4.7 µH + 10 µH + 22 µH in series at 10 MHz.

Leq = 4.7 + 10 + 22 = 36.7 µH

XL = 2π × 10⁷ × 36.7×10⁻⁶ = 2306 Ω ≈ 2.31 kΩ

Example 3: Mutual Inductance — Aiding vs Opposing

Problem: Two 10 mH inductors in series, mutual inductance M = 3 mH. Find Leq for both cases.

Aiding: Leq = 10 + 10 + 2(3) = 26 mH

Opposing: Leq = 10 + 10 − 2(3) = 14 mH

Without coupling: Leq = 20 mH — coupling makes a 30% difference!

Series vs Parallel Inductors — Complete Comparison

Inductors in SeriesInductors in Parallel
FormulaLeq = ΣLi1/Leq = Σ(1/Li)
Result vs individualAlways > largest LAlways < smallest L
Current through eachSame (series)Divides (inversely with L)
Voltage across eachDivides (proportional to L)Same on all
Analogous to resistorsResistors in seriesResistors in parallel
Analogous to capacitorsCapacitors in parallelCapacitors in series
Used forIncreasing L, filter design, EMI chokesCurrent sharing, fine-tuning L, multi-phase

Inductance Units Reference

UnitSymbolValue in HenriesTypical Use
HenryH1 HLarge power-line chokes, transformers
MillihenrymH10⁻³ HAudio filters, DC-DC converter chokes
MicrohenryµH10⁻⁶ HSwitching supplies, RF inductors
NanohenrynH10⁻⁹ HRF, high-frequency, PCB trace inductance

Common Inductor Types and Series Behaviour

TypeInductance RangeKey FeatureSeries Use Case
Air-core coilnH – µHNo saturation, low loss at RFRF filters, tuned circuits
Ferrite-coreµH – mHHigh permeability, compactEMI chokes, switching converters
Iron-powder toroidµH – mHHigh saturation currentPower inductors, DC-DC chokes
Ferrite beadImpedance specHigh-frequency lossMulti-stage EMI suppression
Chip inductor (SMD)nH – µHSmall, high SRFRF, power management ICs

Practical Applications

Common Mistakes to Avoid

Frequently Asked Questions

Do inductors in series always add up?

Only when there is no mutual coupling (M = 0) — the inductors are physically separated or magnetically shielded. If fields interact, use Leq = L1 + L2 ± 2M.

What happens to inductive reactance when inductors are added in series?

XL(total) = 2πf × Leq increases directly with Leq. Adding more inductors in series raises total impedance at every frequency.

Can I mix different core types in series?

Yes. Ferrite, air-core, and iron-powder inductors can all be combined in series — their inductances simply add. Ensure each type can handle the common series current without saturating.

What is the coupling coefficient k?

k = M / √(L₁ × L₂), ranging from 0 (no coupling) to 1 (perfect coupling). Tightly wound bifilar coils approach k = 1; well-separated coils have k ≈ 0.

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